On peut m'aider svp ? ​

1 )

H = ( x - 5 )( x + 1 ) + ( x - 5 )(2x - 3 )

= ( x² + x - 5x - 5 ) + ( 2x²  - 3x - 10x + 15 )

= 3x² + 3x + 10

2 )

H= ( x - 5 )( x + 1 + 2x - 3 )

= ( x - 5 )( 3x - 2 )

a ) x = 0

H = ( 0 - 5 )( 3 × 0 - 2 )

= 10

b )

x = 5

H ( 5 - 5 )( 3 × 5 - 2)

= 0 × 13

= 0

c )

H = 0

( x - 5 )( 3x - 2 ) = 0

x - 5 = 0 ou 3x - 2 = 0

x = 5 ou x = 2/3

Sℝ = { 2/3 ; 5 }